10=-16x^2+64x

Solution for 10=-16x^2+64x equation:

10=-16x^2+64x

We move all terms to the left:

10-(-16x^2+64x)=0

We get rid of parentheses

16x^2-64x+10=0

a = 16; b = -64; c = +10;
Δ = b2-4ac
Δ = -642-4·16·10
Δ = 3456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3456}=\sqrt{576*6}=\sqrt{576}*\sqrt{6}=24\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-24\sqrt{6}}{2*16}=\frac{64-24\sqrt{6}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+24\sqrt{6}}{2*16}=\frac{64+24\sqrt{6}}{32}
$